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6y^2+y-64=0
a = 6; b = 1; c = -64;
Δ = b2-4ac
Δ = 12-4·6·(-64)
Δ = 1537
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{1537}}{2*6}=\frac{-1-\sqrt{1537}}{12} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{1537}}{2*6}=\frac{-1+\sqrt{1537}}{12} $
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